What are the roots of f(x)=6x2+216 ?(1 point)

To find the roots of the function \( f(x) = 6x^2 + 216 \), we first set \( f(x) \) equal to zero:

\[ 6x^2 + 216 = 0 \]

Next, we can simplify this equation:

\[ 6x^2 = -216 \] \[ x^2 = -36 \]

Taking the square root of both sides, we get:

\[ x = \pm \sqrt{-36} \] \[ x = \pm 6i \]

Therefore, the roots of \( f(x) = 6x^2 + 216 \) are:

\[ \pm 6i \]

So the correct response is ±6i (or plus or minus 6 i).