Show how many solutions are in the solution set for the equation 3x2=21

To solve the equation \(3x^2 = 21\), we first isolate \(x^2\):

1. Divide both sides by 3: \[ x^2 = \frac{21}{3} \] \[ x^2 = 7 \]

2. Now, take the square root of both sides: \[ x = \pm \sqrt{7} \]

This means there are two solutions: \(x = \sqrt{7}\) and \(x = -\sqrt{7}\).

Thus, the correct response is:

two