Question
Which of the following is a factor of x3−5x2−2x+24
, given that x - 3 is one of the linear factors?(1 point)
Responses
x2−8x+22
x squared minus 8 x plus 22
x−2
x minus 2
x+2
x plus 2
x+4
, given that x - 3 is one of the linear factors?(1 point)
Responses
x2−8x+22
x squared minus 8 x plus 22
x−2
x minus 2
x+2
x plus 2
x+4
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the other factor of the polynomial \( x^3 - 5x^2 - 2x + 24 \) given that \( x - 3 \) is a factor, we can use polynomial long division or synthetic division.
Since \( x - 3 \) is a factor, we can perform synthetic division with the root \( x = 3 \):
1. Write the coefficients of the polynomial: \( 1, -5, -2, 24 \).
2. Set up synthetic division:
\[
\begin{array}{r|rrrr}
3 & 1 & -5 & -2 & 24 \\
& & 3 & -6 & -24 \\
\hline
& 1 & -2 & -8 & 0 \\
\end{array}
\]
The result of synthetic division gives us the polynomial \( x^2 - 2x - 8 \).
Now we can factor \( x^2 - 2x - 8 \):
\[
x^2 - 2x - 8 = (x - 4)(x + 2)
\]
Thus, the complete factorization of \( x^3 - 5x^2 - 2x + 24 \) is:
\[
(x - 3)(x - 4)(x + 2)
\]
From the options provided, \( x + 2 \) is indeed a factor.
So the answer is:
**x + 2** (x plus 2)
Since \( x - 3 \) is a factor, we can perform synthetic division with the root \( x = 3 \):
1. Write the coefficients of the polynomial: \( 1, -5, -2, 24 \).
2. Set up synthetic division:
\[
\begin{array}{r|rrrr}
3 & 1 & -5 & -2 & 24 \\
& & 3 & -6 & -24 \\
\hline
& 1 & -2 & -8 & 0 \\
\end{array}
\]
The result of synthetic division gives us the polynomial \( x^2 - 2x - 8 \).
Now we can factor \( x^2 - 2x - 8 \):
\[
x^2 - 2x - 8 = (x - 4)(x + 2)
\]
Thus, the complete factorization of \( x^3 - 5x^2 - 2x + 24 \) is:
\[
(x - 3)(x - 4)(x + 2)
\]
From the options provided, \( x + 2 \) is indeed a factor.
So the answer is:
**x + 2** (x plus 2)
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