Two systems of equations are given below. For each system, choose the best description of its solution. applicable, give the solution. If ? 00 System A 3x-y=-8 -3x+y=8 The system has no solution. The system has a unique solution: (x,y) =) The system has infinitely many solutions. The system has no solution. The system has a unique solution: System B x+3y=11 (x,y) = () The system has infinitely many solutions. X 5 Submit Assignment -x+3y=7

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To analyze both systems of equations given, we'll identify whether they have a unique solution, infinitely many solutions, or no solution.

System A:

  1. Equations: \[ 3x - y = -8 \quad (1) \] \[ -3x + y = 8 \quad (2) \]

  2. Rearranging the equations for comparison:

    • From equation (1): \( y = 3x + 8 \)
    • From equation (2): \( y = 3x + 8 \)
  3. Analysis: The two equations are identical, which means they represent the same line. Thus, there are infinitely many solutions.

Conclusion for System A: The system has infinitely many solutions.

System B:

  1. Equations: \[ x + 3y = 11 \quad (3) \] \[ -x + 3y = 7 \quad (4) \]

  2. Rearranging the equations:

    • From equation (3): \( 3y = 11 - x \) or \( y = \frac{11 - x}{3} \)
    • From equation (4): \( 3y = 7 + x \) or \( y = \frac{7 + x}{3} \)
  3. Setting the equations for \(y\) equal to find \(x\): \[ \frac{11 - x}{3} = \frac{7 + x}{3} \]

  4. Multiplying both sides by 3 to eliminate the denominator: \[ 11 - x = 7 + x \]

  5. Solving for \(x\): \[ 11 - 7 = 2x \ 4 = 2x \ x = 2 \]

  6. Substituting \(x = 2\) back into one of the original equations to find \(y\): Using equation (3): \[ 2 + 3y = 11 \quad \Rightarrow \quad 3y = 9 \quad \Rightarrow \quad y = 3 \]

Conclusion for System B: The system has a unique solution: \((x, y) = (2, 3)\).

Final Descriptions:

  • System A: The system has infinitely many solutions.
  • System B: The system has a unique solution: \((x, y) = (2, 3)\).