To find the solution set for the system of inequalities given by:
- \( x + 2y < -2 \)
- \( y - x < 3 \)
We can solve each inequality step by step.
Step 1: Convert inequalities to slope-intercept form (y = mx + b)
For the first inequality: \[ x + 2y < -2 \]
Rearranging it: \[ 2y < -x - 2 \] \[ y < -\frac{1}{2}x - 1 \]
For the second inequality: \[ y - x < 3 \]
Rearranging it: \[ y < x + 3 \]
Step 2: Graph the boundary lines
-
For \( y = -\frac{1}{2}x - 1 \):
- This is a line with a slope of -1/2 and y-intercept at -1.
- The line should be dashed since the inequality is "<", indicating that points on the line are not included in the solution.
-
For \( y = x + 3 \):
- This line has a slope of 1 and a y-intercept at 3.
- Similarly, this line should also be dashed.
Step 3: Determine the shaded regions
-
For \( y < -\frac{1}{2}x - 1 \):
- Shade the area below the line \( y = -\frac{1}{2}x - 1 \).
-
For \( y < x + 3 \):
- Shade the area below the line \( y = x + 3 \).
Step 4: Identify the intersection of the shaded areas
The solution set for the system of inequalities is the region where the areas shaded for both inequalities overlap.
Conclusion
When graphing these inequalities, you should find a region in the coordinate plane that lies below both dashed lines, which indicates the solution set for the system. You can check various points in this intersection area to ensure they satisfy both original inequalities.
If you have specific graphs provided to reference, look for the graph that shows the region below both lines and ensure it does not include the lines themselves, reflecting the '<' type inequalities.