To solve the system of equations using substitution, we will substitute the expression for \( y \) from one equation into the other.
We have the two equations:
- \( y = -3x + 8 \)
- \( y = -x - 4 \)
Since both equations equal \( y \), we can set them equal to each other: \[ -3x + 8 = -x - 4 \]
Next, we will solve for \( x \). First, we can add \( 3x \) to both sides: \[ 8 = 2x - 4 \]
Now, we will add \( 4 \) to both sides: \[ 12 = 2x \]
Next, divide both sides by \( 2 \): \[ x = 6 \]
Now that we have the value of \( x \), we can substitute it back into one of the original equations to find \( y \). Let's use the first equation: \[ y = -3(6) + 8 \] \[ y = -18 + 8 \] \[ y = -10 \]
So, the solution to the system of equations is: \[ (x, y) = (6, -10) \]
To summarize, the solution is \( (6, -10) \).