Solve the following system of equations algebraically:

y, equals, x, squared, minus, x, minus, 65
y=
x
2
−x−65
y, equals, minus, x, minus, 1
y=
−x−1

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To solve the system of equations given by:

  1. \( y = x^2 - x - 65 \)
  2. \( y = -x - 1 \)

we can set the two expressions for \( y \) equal to each other:

\[ x^2 - x - 65 = -x - 1 \]

Next, let's simplify this equation. We'll start by adding \( x + 1 \) to both sides:

\[ x^2 - x - 65 + x + 1 = 0 \]

This simplifies to:

\[ x^2 - 64 = 0 \]

Now, we can factor the equation:

\[ (x - 8)(x + 8) = 0 \]

Setting each factor to zero, we have:

  1. \( x - 8 = 0 \) ⟹ \( x = 8 \)
  2. \( x + 8 = 0 \) ⟹ \( x = -8 \)

Now we will find the corresponding \( y \) values for each \( x \):

For \( x = 8 \):

Using the second equation \( y = -x - 1 \):

\[ y = -8 - 1 = -9 \]

This gives the first solution:

\[ (8, -9) \]

For \( x = -8 \):

Again, using the second equation \( y = -x - 1 \):

\[ y = -(-8) - 1 = 8 - 1 = 7 \]

This gives the second solution:

\[ (-8, 7) \]

Therefore, the solution set for the system of equations is:

\[ \boxed{(8, -9) \text{ and } (-8, 7)} \]