To find the range of the function \( f(x) = 4x - 2 \) with the given domain \({-2, -1, 0, 1, 2}\), we need to calculate \( f(x) \) for each value in the domain:
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For \( x = -2 \): \[ f(-2) = 4(-2) - 2 = -8 - 2 = -10 \]
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For \( x = -1 \): \[ f(-1) = 4(-1) - 2 = -4 - 2 = -6 \]
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For \( x = 0 \): \[ f(0) = 4(0) - 2 = 0 - 2 = -2 \]
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For \( x = 1 \): \[ f(1) = 4(1) - 2 = 4 - 2 = 2 \]
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For \( x = 2 \): \[ f(2) = 4(2) - 2 = 8 - 2 = 6 \]
Now we can collect all the results:
- \( f(-2) = -10 \)
- \( f(-1) = -6 \)
- \( f(0) = -2 \)
- \( f(1) = 2 \)
- \( f(2) = 6 \)
The range of the function is the set of all outputs from these calculations: \[ \text{Range} = {-10, -6, -2, 2, 6} \]
Now, let's match this with the given response options. The correct range is: \[ {-10, -6, -2, 2, 6} \]
Thus, the correct answer is: {-10, -6, -2, 2, 6}