Compare √42 and √58 plotted on the number line. What is the approximate difference in tenths between the two values?

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To compare \(\sqrt{42}\) and \(\sqrt{58}\) and find the difference between their approximate values, we can first estimate each square root.

  1. Estimate \(\sqrt{42}\):

    • We know that \(6^2 = 36\) and \(7^2 = 49\), so \(6 < \sqrt{42} < 7\).
    • To get a closer estimate, we can use approximate values: \[ \sqrt{42} \approx 6.4\ \text{(since } 6.4^2 = 40.96 \text{, which is close to 42)} \]
  2. Estimate \(\sqrt{58}\):

    • We know that \(7^2 = 49\) and \(8^2 = 64\), so \(7 < \sqrt{58} < 8\).
    • For a closer approximation: \[ \sqrt{58} \approx 7.6\ \text{(since } 7.6^2 = 57.76 \text{, which is close to 58)} \]

Now that we have estimated both square roots:

  • \(\sqrt{42} \approx 6.4\)
  • \(\sqrt{58} \approx 7.6\)

Next, we can calculate the difference: \[ \sqrt{58} - \sqrt{42} \approx 7.6 - 6.4 = 1.2 \]

To find the approximate difference in tenths:

  • Since \(1.2\) can also be written as \(12\) tenths, the approximate difference in tenths between \(\sqrt{58}\) and \(\sqrt{42}\) is 12 tenths.

Thus, the approximate difference in tenths between \(\sqrt{42}\) and \(\sqrt{58}\) is \(\boxed{1.2}\).