Question
Walter is using the iterative process to determine that √13 is between 3.61 and
3.62. Analyze Walter's estimation. Is he correct? If not, what mistake did he make? (1 point)
* Yes, Walter is correct.
* No, both 3.61^2 and 3.62^2 are less than 13.
O No, 3.61^2 is less than 13.
O No, both 3.61^2 and 3.62^2 are greater than 13.
3.62. Analyze Walter's estimation. Is he correct? If not, what mistake did he make? (1 point)
* Yes, Walter is correct.
* No, both 3.61^2 and 3.62^2 are less than 13.
O No, 3.61^2 is less than 13.
O No, both 3.61^2 and 3.62^2 are greater than 13.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To verify Walter's estimation of \( \sqrt{13} \) being between \( 3.61 \) and \( 3.62 \), we need to calculate \( 3.61^2 \) and \( 3.62^2 \):
1. Calculate \( 3.61^2 \):
\[
3.61^2 = 12.9921
\]
2. Calculate \( 3.62^2 \):
\[
3.62^2 = 13.0644
\]
Now we compare these results to 13:
- \( 3.61^2 = 12.9921 < 13 \)
- \( 3.62^2 = 13.0644 > 13 \)
From this, we can conclude that \( \sqrt{13} \) falls between \( 3.61 \) and \( 3.62 \).
Walter is correct.
The correct answer is: **Yes, Walter is correct.**
1. Calculate \( 3.61^2 \):
\[
3.61^2 = 12.9921
\]
2. Calculate \( 3.62^2 \):
\[
3.62^2 = 13.0644
\]
Now we compare these results to 13:
- \( 3.61^2 = 12.9921 < 13 \)
- \( 3.62^2 = 13.0644 > 13 \)
From this, we can conclude that \( \sqrt{13} \) falls between \( 3.61 \) and \( 3.62 \).
Walter is correct.
The correct answer is: **Yes, Walter is correct.**
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