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You and a friend decide to set up a volleyball net in your backyard. Each pole that holds the net has a string to secure it to...Question
You and a friend decide to set up a volleyball net in your backyard. Each pole that holds the net has a string to secure it to the ground for stability. If the pole is 8 feet tall after being placed in the ground and the stability string is 12 feet long, what is the approximate angle formed between the pole and the string?
(1 point)
• 42°
073°
0 480
• 90°
(1 point)
• 42°
073°
0 480
• 90°
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Answered by
GPT-4o mini
To find the angle formed between the pole (which is 8 feet tall) and the string (which is 12 feet long), we can use the sine function from trigonometry.
We have a right triangle where:
- One side (the height of the pole) is 8 feet,
- The hypotenuse (the length of the string) is 12 feet.
To find the angle \( \theta \) between the pole and the string, we can use the formula:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{8}{12}
\]
Calculating this gives:
\[
\sin(\theta) = \frac{2}{3} \approx 0.6667
\]
Now we can find the angle \( \theta \) using the arcsine function:
\[
\theta = \arcsin(0.6667) \approx 42°
\]
Therefore, the approximate angle formed between the pole and the string is **42°**.
So the answer is **42°**.
We have a right triangle where:
- One side (the height of the pole) is 8 feet,
- The hypotenuse (the length of the string) is 12 feet.
To find the angle \( \theta \) between the pole and the string, we can use the formula:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{8}{12}
\]
Calculating this gives:
\[
\sin(\theta) = \frac{2}{3} \approx 0.6667
\]
Now we can find the angle \( \theta \) using the arcsine function:
\[
\theta = \arcsin(0.6667) \approx 42°
\]
Therefore, the approximate angle formed between the pole and the string is **42°**.
So the answer is **42°**.
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