Question

Which value of x will make (x, 63, 65) a Pythagorean triple?
(1 point)
0 x =18,194
0 x=2
0 x = 256
• x = 16

Answer 1

To determine which value of \( x \) will make \( (x, 63, 65) \) a Pythagorean triple, we need to check if \( x^2 + 63^2 = 65^2 \).

First, calculate \( 63^2 \) and \( 65^2 \):

\[
63^2 = 3969
\]

\[
65^2 = 4225
\]

Now, we can set up the equation:

\[
x^2 + 3969 = 4225
\]

Subtract 3969 from both sides:

\[
x^2 = 4225 - 3969
\]

Calculate the right side:

\[
4225 - 3969 = 256
\]

So, we have:

\[
x^2 = 256
\]

Taking the square root of both sides gives:

\[
x = 16
\]

Thus, the value of \( x \) that makes \( (x, 63, 65) \) a Pythagorean triple is:

\[
\boxed{16}
\]