two systems of equations are shown:4x+y=−1 x+y=2 and8x+2y=−2 −4x+cy=−8 What would the value of c need to be to get the same solution for both systems?(1 point)Responses4422-4-411-2

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2 hours ago

To find the value of \( c \) such that both systems of equations have the same solution, we first need to determine the solution to the first system of equations.

The first system is:

  1. \( 4x + y = -1 \)
  2. \( x + y = 2 \)

We can solve for \( y \) in terms of \( x \) using the second equation: \[ y = 2 - x. \]

Next, we substitute this expression for \( y \) into the first equation: \[ 4x + (2 - x) = -1 \] \[ 4x + 2 - x = -1 \] Combine like terms: \[ 3x + 2 = -1 \] Subtract 2 from both sides: \[ 3x = -3 \] Divide by 3: \[ x = -1. \]

Now we can substitute \( x = -1 \) back into the equation for \( y \): \[ y = 2 - (-1) = 2 + 1 = 3. \]

So the solution to the first system is \( (x, y) = (-1, 3) \).

Now we will use the second system of equations to find the value of \( c \) that will yield the same solution \( (x, y) = (-1, 3) \).

The second system is:

  1. \( 8x + 2y = -2 \)
  2. \( -4x + cy = -8 \)

First, we substitute \( x = -1 \) and \( y = 3 \) into the first equation of the second system: \[ 8(-1) + 2(3) = -2 \] \[ -8 + 6 = -2 \] This is true, so the first equation in the second system has the same solution.

Next, we need to substitute \( x = -1 \) and \( y = 3 \) into the second equation to find \( c \): \[ -4(-1) + c(3) = -8 \] \[ 4 + 3c = -8 \] Subtract 4 from both sides: \[ 3c = -12 \] Divide by 3: \[ c = -4. \]

Thus, the value of \( c \) needed to get the same solution for both systems is \( -4 \).

So the answer is: \[-4\]