To create an equivalent system, we can manipulate the existing equations in System B to see which option maintains their equivalence. The equations present in System B are:
- \( x + y = 11 \)
Now, let’s consider the options one by one:
-
\( 2x + 2y = 12 \):
- To check if it's equivalent, we can divide the entire equation by 2:
- \( x + y = 6 \)
- This is not equivalent to \( x + y = 11 \).
-
\( -2x - 2y = -22 \):
- Dividing the entire equation by -2 gives:
- \( x + y = 11 \)
- This is equivalent to \( x + y = 11 \).
-
\( -x - y = -1 \):
- To check equivalence, we can multiply the equation by -1 to get:
- \( x + y = 1 \)
- This is also not equivalent to \( x + y = 11 \).
-
\( 2y = 12 \):
- Dividing the entire equation by 2 gives:
- \( y = 6 \)
- This does not relate directly to \( x + y = 11 \) in an equivalent way.
The only option that results in an equivalent equation to \( x + y = 11 \) is:
\( -2x - 2y = -22 \).
So, the answer is:
−2x−2y=−22.