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The graph shows the equation y=13x−2 in red and the equation y=−x+2 in blue. (2 points) What ordered pair is the solution of th...Asked by nuh uhhhhhhhh
The graph shows the equation y=13x−2
in red and the equation y=−x+2
in blue.
(2 points)
What ordered pair is the solution of these two equations?
(
,
)
in red and the equation y=−x+2
in blue.
(2 points)
What ordered pair is the solution of these two equations?
(
,
)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the solution of the two equations \( y = 13x - 2 \) and \( y = -x + 2 \), we need to find the point where the two lines intersect. This means we can set the two equations equal to each other:
\[
13x - 2 = -x + 2
\]
Now, solve for \( x \):
1. Add \( x \) to both sides:
\[
13x + x - 2 = 2
\]
This simplifies to:
\[
14x - 2 = 2
\]
2. Next, add \( 2 \) to both sides:
\[
14x = 4
\]
3. Now, divide by \( 14 \):
\[
x = \frac{4}{14} = \frac{2}{7}
\]
Now that we have the value of \( x \), we can substitute it back into either equation to find the corresponding \( y \). Let's use \( y = -x + 2 \):
\[
y = -\frac{2}{7} + 2
\]
Convert \( 2 \) to a fraction:
\[
y = -\frac{2}{7} + \frac{14}{7} = \frac{12}{7}
\]
Thus, the ordered pair that is the solution to the two equations is:
\[
\left( \frac{2}{7}, \frac{12}{7} \right)
\]
So, the answer is:
\[
\left( \frac{2}{7}, \frac{12}{7} \right)
\]
\[
13x - 2 = -x + 2
\]
Now, solve for \( x \):
1. Add \( x \) to both sides:
\[
13x + x - 2 = 2
\]
This simplifies to:
\[
14x - 2 = 2
\]
2. Next, add \( 2 \) to both sides:
\[
14x = 4
\]
3. Now, divide by \( 14 \):
\[
x = \frac{4}{14} = \frac{2}{7}
\]
Now that we have the value of \( x \), we can substitute it back into either equation to find the corresponding \( y \). Let's use \( y = -x + 2 \):
\[
y = -\frac{2}{7} + 2
\]
Convert \( 2 \) to a fraction:
\[
y = -\frac{2}{7} + \frac{14}{7} = \frac{12}{7}
\]
Thus, the ordered pair that is the solution to the two equations is:
\[
\left( \frac{2}{7}, \frac{12}{7} \right)
\]
So, the answer is:
\[
\left( \frac{2}{7}, \frac{12}{7} \right)
\]
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