Select the inequality that is represented by the blue region of the graph.

Question

(1 point)
Responses

y≤3x−1
y is less than or equal to 3 x minus 1

x>3y−1
x is greater than 3 y minus 1

y>3x−1
y is greater than 3 x minus 1

y<1−3x
y<1−3x
Question 2
Which of the following ordered pairs is a solution to the inequality?(1 point)
Responses

(0,−3)
open paren 0 comma negative 3 close paren

(1,2)
open paren 1 comma 2 close paren

(0,0)
open paren 0 comma 0 close paren

(3,1)

Answer 1

To answer both questions accurately, I need to analyze the graph you referenced, but since I don’t have access to visuals, I can give you some guidance on how to determine the correct inequality and the related ordered pair.

1. Determining the Inequality:

   • If the blue region is below the line represented by \(y = 3x - 1\), the inequality would be \(y \leq 3x - 1\).
   • If the blue region is above the line represented by \(y = 3x - 1\), the inequality would be \(y > 3x - 1\).
   • If the blue region is below the line represented by \(y = 1 - 3x\), the inequality would be \(y < 1 - 3x\).
   • The choice of \(x > 3y - 1\) is less common and represents a region that is a little different from the other forms, so it's unlikely to fit with the standard slope-intercept form.

2. Finding the Ordered Pair:

   • You can substitute each of the ordered pairs into the chosen inequality to see which one satisfies it.
   • For example, if you chose \(y \leq 3x - 1\) as the inequality, plug in the values for \(x\) and \(y\):
     • For (0, -3): \(-3 \leq 3(0) - 1\) → \(-3 \leq -1\) (false)
     • For (1, 2): \(2 \leq 3(1) - 1\) → \(2 \leq 2\) (true)
     • For (0, 0): \(0 \leq 3(0) - 1\) → \(0 \leq -1\) (false)
     • For (3, 1): \(1 \leq 3(3) - 1\) → \(1 \leq 8\) (true)

Pick the inequality that aligns with the blue region, and then confirm the correct ordered pair from your options. If you have further details on the graph or need assistance with a specific part, feel free to share!