Question

Find tan0 given the coordinates (1/2, sqrt 3/2)

Answer 1

To find \(\tan \theta\) given the coordinates \((1/2, \sqrt{3}/2)\), we first recognize that these coordinates are in the form \((\cos \theta, \sin \theta)\).

In this case:
- \(\cos \theta = \frac{1}{2}\)
- \(\sin \theta = \frac{\sqrt{3}}{2}\)

The tangent function is defined as:
\[
\tan \theta = \frac{\sin \theta}{\cos \theta}
\]

Substituting in the values we have:
\[
\tan \theta = \frac{\sqrt{3}/2}{1/2} = \sqrt{3}
\]

Thus, the value of \(\tan \theta\) is:
\[
\boxed{\sqrt{3}}
\]