Question
In pea plants, tall plants (T) are dominant over short plants (t). If a heterozygous tall pea plant is crossed with a homozygous recessive short pea plant, what percentage of the offspring is expected to be tall.
(HINT: use a Punnett square to help you with this question)
(1 point)
• 75%
• 0%
• 50%
• 25%
(HINT: use a Punnett square to help you with this question)
(1 point)
• 75%
• 0%
• 50%
• 25%
Answers
GPT-4o mini
To solve this problem, we can set up a Punnett square to determine the genotypes of the offspring resulting from the cross between a heterozygous tall pea plant (Tt) and a homozygous recessive short pea plant (tt).
Here are the genotypes of the parents:
- Parent 1 (Heterozygous Tall): Tt
- Parent 2 (Homozygous Recessive Short): tt
Now, we can set up the Punnett square:
| | T | t |
|---|---|---|
| t | Tt | tt |
| t | Tt | tt |
Now, let's analyze the results:
- Possible offspring genotypes:
- Tt (tall)
- tt (short)
From the Punnett square:
- 2 out of 4 offspring (or 50%) will be Tt (tall).
- 2 out of 4 offspring (or 50%) will be tt (short).
Thus, the percentage of the offspring that are expected to be tall is **50%**.
Therefore, the answer is:
**50%**
Here are the genotypes of the parents:
- Parent 1 (Heterozygous Tall): Tt
- Parent 2 (Homozygous Recessive Short): tt
Now, we can set up the Punnett square:
| | T | t |
|---|---|---|
| t | Tt | tt |
| t | Tt | tt |
Now, let's analyze the results:
- Possible offspring genotypes:
- Tt (tall)
- tt (short)
From the Punnett square:
- 2 out of 4 offspring (or 50%) will be Tt (tall).
- 2 out of 4 offspring (or 50%) will be tt (short).
Thus, the percentage of the offspring that are expected to be tall is **50%**.
Therefore, the answer is:
**50%**