Question

the average tectonic plat moves at the rate of 0.006m per year how many meters would it move in 2x10^6 years

Answer 1

To find out how far a tectonic plate would move in \(2 \times 10^6\) years at a rate of \(0.006\) meters per year, you can use the formula:

\[
\text{Distance} = \text{Rate} \times \text{Time}
\]

Substituting in the values:

\[
\text{Distance} = 0.006 \, \text{meters/year} \times 2 \times 10^6 \, \text{years}
\]

Calculating this gives:

\[
\text{Distance} = 0.006 \times 2 \times 10^6 = 0.012 \times 10^6 = 12000 \, \text{meters}
\]

So, the tectonic plate would move **12,000 meters** in \(2 \times 10^6\) years.