the average tectonic plat moves at the rate of 0.006m per year how many meters would it move in 2x10^6 years

To find out how far a tectonic plate would move in \(2 \times 10^6\) years at a rate of \(0.006\) meters per year, you can use the formula:

\[ \text{Distance} = \text{Rate} \times \text{Time} \]

Substituting in the values:

\[ \text{Distance} = 0.006 , \text{meters/year} \times 2 \times 10^6 , \text{years} \]

Calculating this gives:

\[ \text{Distance} = 0.006 \times 2 \times 10^6 = 0.012 \times 10^6 = 12000 , \text{meters} \]

So, the tectonic plate would move 12,000 meters in \(2 \times 10^6\) years.