To simplify the expression \(12(x+4) + 14(4x-2)\), let's first distribute the terms in each part of the expression.
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Distributing \(12\) in \(12(x + 4)\): \[ 12(x + 4) = 12x + 48 \]
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Distributing \(14\) in \(14(4x - 2)\): \[ 14(4x - 2) = 56x - 28 \]
Now, combine the results: \[ 12x + 48 + 56x - 28 \]
Next, combine like terms:
- Combine the \(x\) terms: \(12x + 56x = 68x\)
- Combine the constant terms: \(48 - 28 = 20\)
Putting it all together: \[ 68x + 20 \]
To express \(20\) as a mixed number, it is already a whole number and can be considered as \(20\) or \(20\frac{0}{1}\) if you wish to maintain mixed number form.
Thus, the final answer is: \[ 68x + 20 \] or just \(20\) as a mixed number.