Question

if a radius of 5in and a height of 9in what is thevolume of the cone.use 3.14 form pi

Answer 1

The volume \( V \) of a cone can be calculated using the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where:
- \( r \) is the radius of the base of the cone,
- \( h \) is the height of the cone,
- \( \pi \) is a constant (approximately 3.14).

Given:
- Radius \( r = 5 \) inches
- Height \( h = 9 \) inches
- Using \( \pi \approx 3.14 \)

Now plug in the values:

\[
V = \frac{1}{3} \times 3.14 \times (5)^2 \times 9
\]

Calculating \( (5)^2 \):

\[
(5)^2 = 25
\]

Now substitute that back into the formula:

\[
V = \frac{1}{3} \times 3.14 \times 25 \times 9
\]

Next, calculate \( 25 \times 9 \):

\[
25 \times 9 = 225
\]

Now substitute that in:

\[
V = \frac{1}{3} \times 3.14 \times 225
\]

Now multiply \( 3.14 \) and \( 225 \):

\[
3.14 \times 225 = 706.5
\]

Now divide by \( 3 \):

\[
V = \frac{706.5}{3} = 235.5
\]

So, the volume of the cone is approximately \( 235.5 \) cubic inches.