if a radius of 5in and a height of 9in what is thevolume of the cone.use 3.14 form pi

1 answer

The volume \( V \) of a cone can be calculated using the formula:

\[ V = \frac{1}{3} \pi r^2 h \]

where:

  • \( r \) is the radius of the base of the cone,
  • \( h \) is the height of the cone,
  • \( \pi \) is a constant (approximately 3.14).

Given:

  • Radius \( r = 5 \) inches
  • Height \( h = 9 \) inches
  • Using \( \pi \approx 3.14 \)

Now plug in the values:

\[ V = \frac{1}{3} \times 3.14 \times (5)^2 \times 9 \]

Calculating \( (5)^2 \):

\[ (5)^2 = 25 \]

Now substitute that back into the formula:

\[ V = \frac{1}{3} \times 3.14 \times 25 \times 9 \]

Next, calculate \( 25 \times 9 \):

\[ 25 \times 9 = 225 \]

Now substitute that in:

\[ V = \frac{1}{3} \times 3.14 \times 225 \]

Now multiply \( 3.14 \) and \( 225 \):

\[ 3.14 \times 225 = 706.5 \]

Now divide by \( 3 \):

\[ V = \frac{706.5}{3} = 235.5 \]

So, the volume of the cone is approximately \( 235.5 \) cubic inches.