Question
Volume in cubic inches of a cone with a diameter of six inches and a height of seven inches use 3.14 for pi round your answer to the nearest hundredth
Answers
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Answered by
GPT-4o mini
To calculate the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
1. **Find the radius**: The diameter of the cone is 6 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{6}{2} = 3 \text{ inches}
\]
2. **Plug in the values**: The height \( h \) is given as 7 inches. Now substitute \( r \), \( h \), and \( \pi \) into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times (3^2) \times 7
\]
3. **Calculate \( r^2 \)**:
\[
r^2 = 3^2 = 9
\]
4. **Now substitute \( r^2 \) back into the formula**:
\[
V = \frac{1}{3} \times 3.14 \times 9 \times 7
\]
5. **Multiply the values**:
\[
9 \times 7 = 63
\]
\[
V = \frac{1}{3} \times 3.14 \times 63
\]
6. **Calculate \( 3.14 \times 63 \)**:
\[
3.14 \times 63 = 197.82
\]
7. **Finally, divide by 3**:
\[
V = \frac{197.82}{3} \approx 65.94
\]
Thus, the volume of the cone is approximately:
\[
\boxed{65.94} \text{ cubic inches}
\]
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
1. **Find the radius**: The diameter of the cone is 6 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{6}{2} = 3 \text{ inches}
\]
2. **Plug in the values**: The height \( h \) is given as 7 inches. Now substitute \( r \), \( h \), and \( \pi \) into the volume formula:
\[
V = \frac{1}{3} \times 3.14 \times (3^2) \times 7
\]
3. **Calculate \( r^2 \)**:
\[
r^2 = 3^2 = 9
\]
4. **Now substitute \( r^2 \) back into the formula**:
\[
V = \frac{1}{3} \times 3.14 \times 9 \times 7
\]
5. **Multiply the values**:
\[
9 \times 7 = 63
\]
\[
V = \frac{1}{3} \times 3.14 \times 63
\]
6. **Calculate \( 3.14 \times 63 \)**:
\[
3.14 \times 63 = 197.82
\]
7. **Finally, divide by 3**:
\[
V = \frac{197.82}{3} \approx 65.94
\]
Thus, the volume of the cone is approximately:
\[
\boxed{65.94} \text{ cubic inches}
\]
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