To find the equation of a line with a given slope and a point it passes through, you can use the point-slope form of the equation of a line, which is:
\[ y - y_1 = m(x - x_1) \]
where \(m\) is the slope, and \((x_1, y_1)\) is the point on the line.
In this case, the slope \(m = -4\) and the point \((x_1, y_1) = (2, 3)\).
Substituting these values into the equation:
\[ y - 3 = -4(x - 2) \]
Now, simplify the equation:
\[ y - 3 = -4x + 8 \]
\[ y = -4x + 8 + 3 \]
\[ y = -4x + 11 \]
So the equation of the line is:
\[ y = -4x + 11 \]