Show how many solutions are in the solution set for the equation 3x^2=21

To solve the equation \( 3x^2 = 21 \), we can start by isolating the \( x^2 \) term:

1. Divide both sides by 3: \[ x^2 = \frac{21}{3} \] \[ x^2 = 7 \]

2. Now, take the square root of both sides: \[ x = \pm \sqrt{7} \]

This gives us two solutions:

• \( x = \sqrt{7} \)
• \( x = -\sqrt{7} \)

Since there are two distinct solutions, the answer to the question is:

two