To compare the initial values of the two linear functions, we need to identify the initial value (y-intercept) for each function.
Linear Function 1: Taesha starts the year with $50 saved. This indicates her initial value is:
- Initial Value (y-intercept) = $50
Additionally, she saves an additional $25 a week, but the initial amount is what we need for the comparison.
Linear Function 2: The relationship is given by the equation \( y = 37x + 40 \). In this equation, the y-intercept (initial value) is indicated by the constant term when \( x = 0 \):
- Initial Value = $40
Comparison:
- Linear Function 1 has an initial value of $50.
- Linear Function 2 has an initial value of $40.
Since $50 (Linear Function 1) is greater than $40 (Linear Function 2), the conclusion is:
Choose 1 for Linear Function 1.