Question

A scale drawing of triangle ABC
has side lengths of 2
centimeters (cm), 4.8
cm, and 5.2
cm. The scale drawing was drawn using the scale of 1 cm=4 inches.

Raquel creates a different scale drawing of the original triangle ABC
with the scale factor 116.

What are the side lengths in Raquel's scale drawing?

Responses

1
in., 2.4
in., and 2.6
in.
1 in., 2 point 4 in., and 2 point 6 in.

128
in., 307.2
in., and 332.8
in.
128 in., 307 point 2 in., and 332 point 8 in.

0.5
in., 1.2
in., and 1.3
in.
0 point 5 in., 1 point 2 in., and 1 point 3 in.

8
in., 19.2
in., and 20.8
in.
8 in., 19 point 2 in., and 20 point 8 in.
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Answer 1

To find the side lengths in Raquel's scale drawing using the scale factor of \( \frac{1}{16} \), we first need to convert the original side lengths from centimeters to inches, and then apply the scale factor.

The original side lengths of triangle ABC in centimeters are:
- 2 cm
- 4.8 cm
- 5.2 cm

Using the scale of \( 1 \text{ cm} = 4 \text{ inches} \), we convert these lengths to inches:

1. For \( 2 \text{ cm} \):
\[
2 \text{ cm} \times 4 \text{ inches/cm} = 8 \text{ inches}
\]

2. For \( 4.8 \text{ cm} \):
\[
4.8 \text{ cm} \times 4 \text{ inches/cm} = 19.2 \text{ inches}
\]

3. For \( 5.2 \text{ cm} \):
\[
5.2 \text{ cm} \times 4 \text{ inches/cm} = 20.8 \text{ inches}
\]

Now the side lengths of triangle ABC in inches are:
- 8 in.
- 19.2 in.
- 20.8 in.

Next, we apply the scale factor of \( \frac{1}{16} \) to these dimensions:

1. For \( 8 \text{ inches} \):
\[
8 \text{ inches} \times \frac{1}{16} = 0.5 \text{ inches}
\]

2. For \( 19.2 \text{ inches} \):
\[
19.2 \text{ inches} \times \frac{1}{16} = 1.2 \text{ inches}
\]

3. For \( 20.8 \text{ inches} \):
\[
20.8 \text{ inches} \times \frac{1}{16} = 1.3 \text{ inches}
\]

Finally, the side lengths in Raquel's scale drawing are:
- \( 0.5 \, \text{in}, 1.2 \, \text{in}, 1.3 \, \text{in} \)

So, the correct response is:
**0.5 in., 1.2 in., and 1.3 in.**