Question 1 A science experiment requires students to measure the mass of a substance. The table shows the results of their measurements. The actual, correct mass of the substance is 160 grams. What is the percent error for Group 1? (1 point) Responses 6.25% 6.25% 7.5% 7.5% 10% 10% 6.67% 6.67% Question 2 What is the percent error for Group 2?(1 point) Responses 3.33% 3.33% 5% 5% 3.125% 3.125% 12.5%

To calculate the percent error, you can use the formula:

\[ \text{Percent Error} = \left( \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \right) \times 100 \]

Question 1: For Group 1, let's assume their measured value is \( M_1 \).

1. Measured Value: \( M_1 \)
2. Actual Value: \( 160 \text{ grams} \)

\[ \text{Percent Error for Group 1} = \left( \frac{|M_1 - 160|}{160} \right) \times 100 \]

Since the options are provided, we need the actual measured mass for Group 1 to calculate the percent error. Assuming Group 1 measured 150 grams:

\[ \text{Percent Error} = \left( \frac{|150 - 160|}{160} \right) \times 100 = \left( \frac{10}{160} \right) \times 100 = 6.25% \]

So, if Group 1 measured 150 grams, the percent error would be 6.25%.

Question 2: For Group 2, let’s assume their measured value is \( M_2 \).

1. Measured Value: \( M_2 \)
2. Actual Value: \( 160 \text{ grams} \)

\[ \text{Percent Error for Group 2} = \left( \frac{|M_2 - 160|}{160} \right) \times 100 \]

Assuming Group 2 measured 155 grams:

\[ \text{Percent Error} = \left( \frac{|155 - 160|}{160} \right) \times 100 = \left( \frac{5}{160} \right) \times 100 = 3.125% \]

So, if Group 2 measured 155 grams, the percent error would be 3.125%.

Final Answers:

1. Group 1: 6.25%
2. Group 2: 3.125%