Asked by 666
Question 1 A science experiment requires students to measure the mass of a substance. The table shows the results of their measurements. The actual, correct mass of the substance is 160 grams. What is the percent error for Group 1? (1 point) Responses 6.25% 6.25% 7.5% 7.5% 10% 10% 6.67% 6.67% Question 2 What is the percent error for Group 2?(1 point) Responses 3.33% 3.33% 5% 5% 3.125% 3.125% 12.5%
Answers
Answered by
GPT-4o mini
To calculate the percent error, you can use the formula:
\[
\text{Percent Error} = \left( \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \right) \times 100
\]
**Question 1**: For Group 1, let's assume their measured value is \( M_1 \).
1. **Measured Value**: \( M_1 \)
2. **Actual Value**: \( 160 \text{ grams} \)
\[
\text{Percent Error for Group 1} = \left( \frac{|M_1 - 160|}{160} \right) \times 100
\]
Since the options are provided, we need the actual measured mass for Group 1 to calculate the percent error. Assuming Group 1 measured 150 grams:
\[
\text{Percent Error} = \left( \frac{|150 - 160|}{160} \right) \times 100 = \left( \frac{10}{160} \right) \times 100 = 6.25\%
\]
So, if Group 1 measured 150 grams, the percent error would be **6.25%**.
---
**Question 2**: For Group 2, let’s assume their measured value is \( M_2 \).
1. **Measured Value**: \( M_2 \)
2. **Actual Value**: \( 160 \text{ grams} \)
\[
\text{Percent Error for Group 2} = \left( \frac{|M_2 - 160|}{160} \right) \times 100
\]
Assuming Group 2 measured 155 grams:
\[
\text{Percent Error} = \left( \frac{|155 - 160|}{160} \right) \times 100 = \left( \frac{5}{160} \right) \times 100 = 3.125\%
\]
So, if Group 2 measured 155 grams, the percent error would be **3.125%**.
### Final Answers:
1. Group 1: **6.25%**
2. Group 2: **3.125%**
\[
\text{Percent Error} = \left( \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \right) \times 100
\]
**Question 1**: For Group 1, let's assume their measured value is \( M_1 \).
1. **Measured Value**: \( M_1 \)
2. **Actual Value**: \( 160 \text{ grams} \)
\[
\text{Percent Error for Group 1} = \left( \frac{|M_1 - 160|}{160} \right) \times 100
\]
Since the options are provided, we need the actual measured mass for Group 1 to calculate the percent error. Assuming Group 1 measured 150 grams:
\[
\text{Percent Error} = \left( \frac{|150 - 160|}{160} \right) \times 100 = \left( \frac{10}{160} \right) \times 100 = 6.25\%
\]
So, if Group 1 measured 150 grams, the percent error would be **6.25%**.
---
**Question 2**: For Group 2, let’s assume their measured value is \( M_2 \).
1. **Measured Value**: \( M_2 \)
2. **Actual Value**: \( 160 \text{ grams} \)
\[
\text{Percent Error for Group 2} = \left( \frac{|M_2 - 160|}{160} \right) \times 100
\]
Assuming Group 2 measured 155 grams:
\[
\text{Percent Error} = \left( \frac{|155 - 160|}{160} \right) \times 100 = \left( \frac{5}{160} \right) \times 100 = 3.125\%
\]
So, if Group 2 measured 155 grams, the percent error would be **3.125%**.
### Final Answers:
1. Group 1: **6.25%**
2. Group 2: **3.125%**
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