Question

Question 1 A science experiment requires students to measure the mass of a substance. The table shows the results of their measurements. The actual, correct mass of the substance is 160 grams. What is the percent error for Group 1? (1 point) Responses 6.25% 6.25% 7.5% 7.5% 10% 10% 6.67% 6.67% Question 2 What is the percent error for Group 2?(1 point) Responses 3.33% 3.33% 5% 5% 3.125% 3.125% 12.5%

Answer 1

To calculate the percent error, you can use the formula:

$$\text{Percent Error}=\left(\frac{|\text{Measured Value}-\text{Actual Value}|}{\text{Actual Value}}\right)\times 100$$

Question 1: For Group 1, let's assume their measured value is $M_1$.

1. Measured Value: $M_1$
2. Actual Value: $160\text{ grams}$

$$\text{Percent Error for Group 1}=\left(\frac{|M_1-160|}{160}\right)\times 100$$

Since the options are provided, we need the actual measured mass for Group 1 to calculate the percent error. Assuming Group 1 measured 150 grams:

$$\text{Percent Error}=\left(\frac{|150-160|}{160}\right)\times 100=\left(\frac{10}{160}\right)\times 100=6.25$$

So, if Group 1 measured 150 grams, the percent error would be 6.25%.

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Question 2: For Group 2, let’s assume their measured value is $M_2$.

1. Measured Value: $M_2$
2. Actual Value: $160\text{ grams}$

$$\text{Percent Error for Group 2}=\left(\frac{|M_2-160|}{160}\right)\times 100$$

Assuming Group 2 measured 155 grams:

$$\text{Percent Error}=\left(\frac{|155-160|}{160}\right)\times 100=\left(\frac{5}{160}\right)\times 100=3.125$$

So, if Group 2 measured 155 grams, the percent error would be 3.125%.

Final Answers:

1. Group 1: 6.25%
2. Group 2: 3.125%