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Original Question
There is a line that includes the point (4,1) and has a slope of – 1 9 . What is its equation in point-slope form?Asked by gOt MiLk
There is a line that includes the point (3,8) and has a slope of
1
3
. What is its equation in point-slope form?
1
3
. What is its equation in point-slope form?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The point-slope form of the equation of a line is given by the formula:
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
In this case, the point is \((3, 8)\) and the slope \(m\) is \(\frac{1}{3}\). Plugging these values into the point-slope formula gives:
\[
y - 8 = \frac{1}{3}(x - 3)
\]
Thus, the equation of the line in point-slope form is:
\[
y - 8 = \frac{1}{3}(x - 3)
\]
\[
y - y_1 = m(x - x_1)
\]
where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.
In this case, the point is \((3, 8)\) and the slope \(m\) is \(\frac{1}{3}\). Plugging these values into the point-slope formula gives:
\[
y - 8 = \frac{1}{3}(x - 3)
\]
Thus, the equation of the line in point-slope form is:
\[
y - 8 = \frac{1}{3}(x - 3)
\]
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