Complete the division problem.


13 29

A.
2 with a remainder of 3
B.
2
C.
1 with a remainder of 3
D.
5

1 answer

To complete the division problem \( 13 \div 29 \):

Since 13 is less than 29, the division results in 0 when calculating how many times 29 goes into 13.

If we want to express it in terms of a quotient with a remainder, we can write it as:

  • Quotient: 0
  • Remainder: 13

However, since none of the provided choices match this result, we can check how many times 29 would go into 13 if we consider the positive integers.

Since \( 29 > 13 \), it goes 0 times in whole numbers.

But looking at your choices, the relevant choice is:

  • C. 1 with a remainder of 3

This option doesn't directly fit the division of 13 by 29 but assuming you're looking for how 13 exceeds or is considered under modulo in a different way, it seems incorrect in format.

In conclusion, none of the choices matches they all seem incorrect. It's best to state the division as:

  • Quotient: 0
  • Remainder: 13

Could you clarify or correct the problem if needed?