Question

According to the Law of Conservation of Mass, if 88 g of carbon dioxide ( CO2
) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen ( O2
) in the reactants?(1 point)
Responses

24 g
24 g

104 g
104 g

32 g
32 g

64 g
64 g

Answer 1

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products. In this case, you have the following:

- Mass of carbon (C) = 24 g
- Mass of carbon dioxide (CO2) produced = 88 g

To find the mass of dioxygen (O2) in the reactants, you can use the following equation:

\[
\text{Mass of reactants} = \text{Mass of products}
\]

The mass of dioxygen (O2) can be found using:

\[
\text{Mass of O2} = \text{Mass of CO2} - \text{Mass of C}
\]

So:

\[
\text{Mass of O2} = 88 \, \text{g} - 24 \, \text{g} = 64 \, \text{g}
\]

Therefore, the mass of dioxygen (O2) in the reactants is **64 g**.