To find the value of \( y \) when \( x = 4 \) in the equation \( y = 2x^2 + 12x - 10 \), substitute \( x \) with 4:
\[ y = 2(4)^2 + 12(4) - 10 \]
Now, calculate each term:
- \( 2(4)^2 = 2 \times 16 = 32 \)
- \( 12(4) = 48 \)
- The constant term is \(-10\).
Now, combine these results:
\[ y = 32 + 48 - 10 \]
Calculating this step-by-step:
\[ 32 + 48 = 80 \] \[ 80 - 10 = 70 \]
Thus, the value of \( y \) when \( x = 4 \) is:
\[ \boxed{70} \]