y=2x^2+12x-10 if x = -4

Answer 1

To find the value of $y$ when $x=-4$ in the equation $y=2x^2+12x-10$, we can substitute $-4$ for $x$:

$$y=2(-4{)}^2+12(-4)-10$$

Calculating each term step-by-step:

1. Calculate $(-4{)}^2$: $$(-4{)}^2=16$$

2. Multiply by 2: $$2\cdot 16=32$$

3. Calculate $12(-4)$: $$12\cdot (-4)=-48$$

Now, substitute these values back into the equation:

$$y=32-48-10$$

Now, perform the subtraction:

1. Calculate $32-48$: $$32-48=-16$$

2. Then, calculate $-16-10$: $$-16-10=-26$$

Thus, the value of $y$ when $x=-4$ is:

$$\boxed{{\displaystyle -26}}$$