y=2x^2+12x-10 if x = -4

Answer 1

To find the value of \( y \) when \( x = -4 \) in the equation \( y = 2x^2 + 12x - 10 \), we can substitute \(-4\) for \( x \):

\[ y = 2(-4)^2 + 12(-4) - 10 \]

Calculating each term step-by-step:

1. Calculate \((-4)^2\): \[ (-4)^2 = 16 \]

2. Multiply by 2: \[ 2 \cdot 16 = 32 \]

3. Calculate \( 12(-4) \): \[ 12 \cdot (-4) = -48 \]

Now, substitute these values back into the equation:

\[ y = 32 - 48 - 10 \]

Now, perform the subtraction:

1. Calculate \( 32 - 48 \): \[ 32 - 48 = -16 \]

2. Then, calculate \(-16 - 10\): \[ -16 - 10 = -26 \]

Thus, the value of \( y \) when \( x = -4 \) is:

\[ \boxed{-26} \]