Asked by lilracist
Find the slope of a line that passes through (-10, -1) and (5, -4).
-15
13
1
-3
-15
13
1
-3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the slope of the line that passes through the points \((-10, -1)\) and \( (5, -4)\), you can use the slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
where \((x_1, y_1)\) is the first point and \((x_2, y_2)\) is the second point.
Here, \((x_1, y_1) = (-10, -1)\) and \((x_2, y_2) = (5, -4)\).
Now, plug in the values:
\[
m = \frac{-4 - (-1)}{5 - (-10)}
\]
This simplifies to:
\[
m = \frac{-4 + 1}{5 + 10} = \frac{-3}{15} = -\frac{1}{5}
\]
The slope \(m\) of the line is \(-\frac{1}{5}\).
It seems there was a small mistake in the options provided, as none match \(-\frac{1}{5}\). Would you like to verify or provide additional information?
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
where \((x_1, y_1)\) is the first point and \((x_2, y_2)\) is the second point.
Here, \((x_1, y_1) = (-10, -1)\) and \((x_2, y_2) = (5, -4)\).
Now, plug in the values:
\[
m = \frac{-4 - (-1)}{5 - (-10)}
\]
This simplifies to:
\[
m = \frac{-4 + 1}{5 + 10} = \frac{-3}{15} = -\frac{1}{5}
\]
The slope \(m\) of the line is \(-\frac{1}{5}\).
It seems there was a small mistake in the options provided, as none match \(-\frac{1}{5}\). Would you like to verify or provide additional information?
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