Barton took out a car loan of $2,625. He makes monthly payments of $175. The graph represents the remaining balance after each payment. Which example models the correct slope?

(1 point)
Responses

m=1,050−1,2259−8
m equals Start Fraction 1,050 minus 1,225 over 9 minus 8 End Fraction

m=9−81,050−1,225
m equals Start Fraction 9 minus 8 over 1,050 minus 1,225 End Fraction

m=525−70011−12
m equals Start Fraction 525 minus 700 over 11 minus 12 End Fraction

m=2,450−2,6250−1

1 answer

To determine the correct slope for Barton’s car loan scenario, we need to consider the definition of slope in the context of his loan payments.

The slope \( m \) is computed using the formula:

\[ m = \frac{\text{change in } y}{\text{change in } x} \]

In this case, \( y \) represents the remaining balance of the loan, and \( x \) represents the number of payments made.

Given:

  • He took out a car loan of $2,625.
  • After each payment of $175, the remaining balance decreases.

The remaining balance after one payment can be represented as:

  • After 1 payment: \( 2,625 - 175 \)
  • After 2 payments: \( 2,625 - 2 \cdot 175 \)

The slope represents the rate of change of the balance with respect to the number of payments made. For each payment made, the balance decreases by $175.

Let's evaluate each provided example to find which expression reflects the correct slope:

  1. \( m = \frac{1,050 - 1,225}{9 - 8} \)

    • Here, the change in balance seems not to match the payment structure correctly.
  2. \( m = \frac{9 - 8}{1,050 - 1,225} \)

    • This essentially results in a very small number and does not represent the payment structure.
  3. \( m = \frac{525 - 700}{11 - 12} \)

    • Again, this doesn't match the decreasing balance by $175 correctly.
  4. \( m = \frac{2,450 - 2,625}{0 - 1} \)

    • This results in \( \frac{-175}{-1} = 175 \), which is the amount by which the balance decreases after each payment.

Therefore, the correct example that models the correct slope is:

\( m = \frac{2,450 - 2,625}{0 - 1} \).