To determine if the point \((-2, 6)\) is a solution to the system of equations, we need to substitute \(x = -2\) and \(y = 6\) into both equations and see if they hold true.
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Substituting into the first equation: \[ x + 2y = 10 \] Substitute \(x = -2\) and \(y = 6\): \[ -2 + 2(6) = -2 + 12 = 10 \] This holds true.
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Substituting into the second equation: \[ 3x + y = 0 \] Substitute \(x = -2\) and \(y = 6\): \[ 3(-2) + 6 = -6 + 6 = 0 \] This also holds true.
Since the point \((-2, 6)\) satisfies both equations, we conclude that \((-2, 6)\) is indeed a solution to the system of equations.