Asked by yeslian c
Re-express 3−32−−−−√
as a complex number with the imaginary unit i=−1−−−√
.(
as a complex number with the imaginary unit i=−1−−−√
.(
Answers
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Answered by
GPT-4o mini
To re-express \( 3 - \sqrt{32} \) as a complex number with the imaginary unit \( i \), we can first simplify the square root of 32.
We can rewrite \( \sqrt{32} \) as:
\[
\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2}
\]
Now substitute this back into the expression:
\[
3 - \sqrt{32} = 3 - 4\sqrt{2}
\]
Next, we express this in terms of \( i \). The imaginary unit \( i \) is defined as:
\[
i = \sqrt{-1}
\]
To relate \( 3 - 4\sqrt{2} \) to the imaginary unit, we can represent it in a complex form. Any real number can be expressed as a complex number with its imaginary part set to zero. Thus we write:
\[
3 - 4\sqrt{2} = (3 - 4\sqrt{2}) + 0i
\]
Therefore, we fully express \( 3 - \sqrt{32} \) as a complex number:
\[
3 - \sqrt{32} = (3 - 4\sqrt{2}) + 0i
\]
This is the expression of \( 3 - \sqrt{32} \) as a complex number where the imaginary part is \( 0 \).
We can rewrite \( \sqrt{32} \) as:
\[
\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2}
\]
Now substitute this back into the expression:
\[
3 - \sqrt{32} = 3 - 4\sqrt{2}
\]
Next, we express this in terms of \( i \). The imaginary unit \( i \) is defined as:
\[
i = \sqrt{-1}
\]
To relate \( 3 - 4\sqrt{2} \) to the imaginary unit, we can represent it in a complex form. Any real number can be expressed as a complex number with its imaginary part set to zero. Thus we write:
\[
3 - 4\sqrt{2} = (3 - 4\sqrt{2}) + 0i
\]
Therefore, we fully express \( 3 - \sqrt{32} \) as a complex number:
\[
3 - \sqrt{32} = (3 - 4\sqrt{2}) + 0i
\]
This is the expression of \( 3 - \sqrt{32} \) as a complex number where the imaginary part is \( 0 \).
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