To convert the base 16 number \( 1C \) to base 10, you can break it down as follows:
- The digit '1' is in the 16's place, which is \( 1 \times 16^1 = 1 \times 16 = 16 \).
- The digit 'C' represents the decimal number 12 in base 16, and it is in the 1's place, which is \( 12 \times 16^0 = 12 \times 1 = 12 \).
Now, add these two values together:
\[ 16 + 12 = 28 \]
Therefore, the base 16 number \( 1C \) is equal to \( 28 \) in base 10.
So the correct response is:
28