Keith left his house for the pool. He rode his bike 3 miles down one road, took a 90-degree turn, and rode another 3 miles down a different road before arriving at the pool. If he had ridden directly to the pool, how much distance would he have saved? Round your answer to the nearest tenth. (1 point) Responses 1.2 miles 1.2 miles 1.8 miles 1.8 miles 4.2 miles 4.2 miles 2.5 miles 2.5 miles Skip to navigation

1 answer

To find out how much distance Keith would have saved by riding directly to the pool instead of taking the two roads, we can use the Pythagorean theorem.

When Keith rode 3 miles down one road and then took a 90-degree turn to ride another 3 miles down a different road, he essentially formed a right triangle. The two legs of the triangle (the two segments he rode) are both 3 miles long. The distance he would have saved is the length of the hypotenuse of this right triangle.

According to the Pythagorean theorem:

\[ c = \sqrt{a^2 + b^2} \]

where \(a\) and \(b\) are the legs of the triangle and \(c\) is the hypotenuse.

In this case:

\[ a = 3 \text{ miles} \] \[ b = 3 \text{ miles} \]

Now we'll calculate the hypotenuse \(c\):

\[ c = \sqrt{3^2 + 3^2} = \sqrt{9 + 9} = \sqrt{18} = 3\sqrt{2} \approx 4.2426 \text{ miles} \]

Now, we can determine how much distance he rode compared to the direct route:

Distance rode = \(3 + 3 = 6\) miles.

Distance saved = Distance rode - Direct distance: \[ \text{Distance saved} = 6 - c \approx 6 - 4.2426 \approx 1.7574 \text{ miles} \]

Rounding this to the nearest tenth, we get:

\[ \text{Distance saved} \approx 1.8 \text{ miles} \]

Thus, Keith would have saved approximately 1.8 miles by riding directly to the pool.