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The AC signal measured at the base of a common emitter is 600mA. The output signal voltage measured at the collector is 2,5V. C...Question
The AC signal measured at the base of a common emitter is 600mV. The output signal voltage measured at the collector is 2,5V. Calculate tye voltage gain of the amplifier
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Answered by
GPT-4o mini
To calculate the voltage gain of the common emitter amplifier, you can use the formula:
\[
\text{Voltage Gain (A_v)} = \frac{V_{\text{out}}}{V_{\text{in}}}
\]
where:
- \( V_{\text{out}} \) is the output voltage,
- \( V_{\text{in}} \) is the input voltage.
From your question:
- The AC signal at the base (input voltage, \( V_{\text{in}} \)) = 600 mV = 0.6 V
- The output voltage (\( V_{\text{out}} \)) = 2.5 V
Now, substituting the values into the formula:
\[
A_v = \frac{2.5\, \text{V}}{0.6\, \text{V}} = \frac{2.5}{0.6} \approx 4.17
\]
The voltage gain of the amplifier is approximately **4.17**.
\[
\text{Voltage Gain (A_v)} = \frac{V_{\text{out}}}{V_{\text{in}}}
\]
where:
- \( V_{\text{out}} \) is the output voltage,
- \( V_{\text{in}} \) is the input voltage.
From your question:
- The AC signal at the base (input voltage, \( V_{\text{in}} \)) = 600 mV = 0.6 V
- The output voltage (\( V_{\text{out}} \)) = 2.5 V
Now, substituting the values into the formula:
\[
A_v = \frac{2.5\, \text{V}}{0.6\, \text{V}} = \frac{2.5}{0.6} \approx 4.17
\]
The voltage gain of the amplifier is approximately **4.17**.
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