To determine if the function represented by the table is linear, we need to check if the rate of change in \( y \) for each unit increase in \( x \) is constant.
Let's look at the given values:
- When \( x = 10 \), \( y = -6 \)
- When \( x = 11 \), \( y = 1 \)
- When \( x = 12 \), \( y = 6 \)
- When \( x = 13 \), \( y = 12 \)
Now, we'll calculate the change in \( y \) for each increase in \( x \):
-
From \( x = 10 \) to \( x = 11 \):
- Change in \( y = 1 - (-6) = 7 \)
-
From \( x = 11 \) to \( x = 12 \):
- Change in \( y = 6 - 1 = 5 \)
-
From \( x = 12 \) to \( x = 13 \):
- Change in \( y = 12 - 6 = 6 \)
Now, we summarize the changes:
- From \( x = 10 \) to \( x = 11 \): change of \( 7 \)
- From \( x = 11 \) to \( x = 12 \): change of \( 5 \)
- From \( x = 12 \) to \( x = 13 \): change of \( 6 \)
Since the changes in \( y \) are not constant (7, 5, and 6 are different), the function does not have a constant rate of change.
Therefore, the correct answer is: No, because it does not have a constant rate of change.