To calculate the quotient \(\dfrac{1.72\times 10^{0}}{4.0\times 10^{-3}}\), we can follow these steps:
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Divide the coefficients: \[ \dfrac{1.72}{4.0} = 0.43 \]
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Apply the properties of exponents: \[ 10^{0} \div 10^{-3} = 10^{0 - (-3)} = 10^{0 + 3} = 10^{3} \]
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Combine the results: Bringing it all together, we get: \[ 0.43 \times 10^{3} \]
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Convert to scientific notation: We need to express \(0.43\) in scientific notation. We can do this by moving the decimal point one place to the right, which gives us \(4.3\) and we must account for that by multiplying by \(10^{-1}\): \[ 0.43 = 4.3 \times 10^{-1} \]
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Combine: Now substitute back into the equation: \[ 0.43 \times 10^{3} = (4.3 \times 10^{-1}) \times 10^{3} = 4.3 \times 10^{3 - 1} = 4.3 \times 10^{2} \]
Thus, the final result in scientific notation is: \[ \boxed{4.3 \times 10^{2}} \]