Question
Is
\[\dfrac{36}{25}\cdot \sqrt{11}\] rational or irrational?
Choose 1 answer:
Choose 1 answer:
(Choice A) Rational
A
Rational
(Choice B) Irrational
B
Irrational
(Choice C) It can be either rational or irrational
C
It can be either rational or irrational
\[\dfrac{36}{25}\cdot \sqrt{11}\] rational or irrational?
Choose 1 answer:
Choose 1 answer:
(Choice A) Rational
A
Rational
(Choice B) Irrational
B
Irrational
(Choice C) It can be either rational or irrational
C
It can be either rational or irrational
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine whether the expression
\[
\dfrac{36}{25} \cdot \sqrt{11}
\]
is rational or irrational, let's analyze each component of the expression:
1. **Rational Number**: The fraction \(\frac{36}{25}\) is a rational number because it is the quotient of two integers (36 and 25).
2. **Irrational Number**: The square root \(\sqrt{11}\) is an irrational number because 11 is not a perfect square.
Now, when we multiply a rational number by an irrational number, the result is always irrational. Therefore,
\[
\dfrac{36}{25} \cdot \sqrt{11}
\]
must be irrational.
Thus, the correct choice is:
**(Choice B) Irrational**.
\[
\dfrac{36}{25} \cdot \sqrt{11}
\]
is rational or irrational, let's analyze each component of the expression:
1. **Rational Number**: The fraction \(\frac{36}{25}\) is a rational number because it is the quotient of two integers (36 and 25).
2. **Irrational Number**: The square root \(\sqrt{11}\) is an irrational number because 11 is not a perfect square.
Now, when we multiply a rational number by an irrational number, the result is always irrational. Therefore,
\[
\dfrac{36}{25} \cdot \sqrt{11}
\]
must be irrational.
Thus, the correct choice is:
**(Choice B) Irrational**.
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