Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Simplify. Remove all perfect squares from inside the square root. \[\sqrt{52x^4}=\]Question
Simplify.
Remove all perfect squares from inside the square root.
\[{\sqrt[]{180}}=\]
Remove all perfect squares from inside the square root.
\[{\sqrt[]{180}}=\]
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify \(\sqrt{180}\), we start by factoring 180 into its prime factors.
First, we can break down 180 as follows:
\[
180 = 18 \times 10
\]
Next, we can factor 18 and 10:
\[
18 = 9 \times 2 = 3^2 \times 2
\]
\[
10 = 5 \times 2
\]
Putting it all together, we have:
\[
180 = 3^2 \times 2 \times 5 \times 2 = 3^2 \times 2^2 \times 5
\]
Now, we rewrite \(180\) using its prime factors:
\[
180 = 2^2 \times 3^2 \times 5
\]
Next, we apply the property of square roots:
\[
\sqrt{180} = \sqrt{2^2 \times 3^2 \times 5}
\]
We can take the square roots of the perfect squares:
\[
\sqrt{180} = \sqrt{2^2} \times \sqrt{3^2} \times \sqrt{5} = 2 \times 3 \times \sqrt{5}
\]
This simplifies to:
\[
\sqrt{180} = 6\sqrt{5}
\]
Thus, the simplified form of \(\sqrt{180}\) is:
\[
\boxed{6\sqrt{5}}
\]
First, we can break down 180 as follows:
\[
180 = 18 \times 10
\]
Next, we can factor 18 and 10:
\[
18 = 9 \times 2 = 3^2 \times 2
\]
\[
10 = 5 \times 2
\]
Putting it all together, we have:
\[
180 = 3^2 \times 2 \times 5 \times 2 = 3^2 \times 2^2 \times 5
\]
Now, we rewrite \(180\) using its prime factors:
\[
180 = 2^2 \times 3^2 \times 5
\]
Next, we apply the property of square roots:
\[
\sqrt{180} = \sqrt{2^2 \times 3^2 \times 5}
\]
We can take the square roots of the perfect squares:
\[
\sqrt{180} = \sqrt{2^2} \times \sqrt{3^2} \times \sqrt{5} = 2 \times 3 \times \sqrt{5}
\]
This simplifies to:
\[
\sqrt{180} = 6\sqrt{5}
\]
Thus, the simplified form of \(\sqrt{180}\) is:
\[
\boxed{6\sqrt{5}}
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.