Complete the recursive formula of the geometric sequence

\[0.2\,,-1\,,\,5\,,-25,\unicode{0x2026}\].
\[a(1)=\]
\[a(n)=a(n-1)\cdot\]

1 answer

To find the recursive formula of the given geometric sequence \(0.2, -1, 5, -25, \ldots\), let's first identify the first term and the common ratio.

  1. The first term is: \[ a(1) = 0.2 \]

  2. To find the common ratio, we can divide any term by the previous term:

    • To find the ratio between the second term and the first term: \[ r = \frac{-1}{0.2} = -5 \]

    • To verify, we can check the ratio between the third term and the second term: \[ r = \frac{5}{-1} = -5 \]

    • Finally, let's check the ratio between the fourth term and the third term: \[ r = \frac{-25}{5} = -5 \]

Since the ratio is consistent across the terms, we confirm the common ratio \(r = -5\).

Putting this information together, we can write the recursive formula for the sequence:

  • The first term: \[ a(1) = 0.2 \]

  • The recursive relationship: \[ a(n) = a(n-1) \cdot (-5) \]

Therefore, the completed recursive formula is:

\[ \begin{align*} a(1) &= 0.2, \ a(n) &= a(n-1) \cdot (-5) \text{ for } n > 1. \end{align*} \]

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