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To find \( f(2) \), we can use the recursive formula given in the problem:
\[
f(n) = 2 \cdot f(n-1) + 1
\]
We also know the base case:
\[
f(1) = -3
\]
Now, we can calculate \( f(2) \):
\[
f(2) = 2 \cdot f(1) + 1
\]
Substituting the value of \( f(1) \):
\[
f(2) = 2 \cdot (-3) + 1
\]
Calculating this gives:
\[
f(2) = -6 + 1 = -5
\]
Therefore, the value of \( f(2) \) is:
\[
\boxed{-5}
\]