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To subtract the expression \(2(k-4) - 3(2k-1)\), we can first distribute the constants in front of the parentheses.
1. Distribute \(2\) in \(2(k-4)\):
\[
2(k-4) = 2k - 8
\]
2. Distribute \(-3\) in \(-3(2k-1)\):
\[
-3(2k-1) = -6k + 3
\]
Now, combine the two results:
\[
2(k-4) - 3(2k-1) = (2k - 8) + (-6k + 3)
\]
Next, we can combine like terms:
\[
= 2k - 6k - 8 + 3
\]
\[
= -4k - 5
\]
Thus, the result of the expression \(2(k-4) - 3(2k-1)\) is:
\[
\boxed{-4k - 5}
\]