Question

A student follows the lab procedure below:



Lab Procedure:



1. Add 15 g water to a 500 mL beaker

2. Add 3 g salt to the beaker

3. Stir the contents of the beaker for 45 seconds

4. Add 8 g vinegar to the beaker


Using the Law of Conservation of Matter, what will be the mass of the contents in the beaker?
Responses
A 11 g
B 4 g
C 26 g
D 15 g

Answer 1

According to the Law of Conservation of Matter, the mass of the substances before and after a chemical reaction or physical change must remain the same, as no mass is lost or gained in the process.

Let's calculate the total mass based on the procedure:

1. Mass of water = 15 g
2. Mass of salt = 3 g
3. Mass of vinegar = 8 g

Now, we sum these masses:
- Total mass = 15 g (water) + 3 g (salt) + 8 g (vinegar) = 26 g

So, the mass of the contents in the beaker will be **26 g**.

The correct response is **C 26 g**.