Is (–4, 0) a solution to the equation y = x2 − 7x?

To determine if the point \((-4, 0)\) is a solution to the equation \(y = x^2 - 7x\), we can substitute \(x = -4\) into the equation and see if \(y\) equals 0.

Starting with the equation:

\[
y = x^2 - 7x
\]

Substituting \(x = -4\):

\[
y = (-4)^2 - 7(-4)
\]

Calculating the terms:

\[
y = 16 + 28
\]

\[
y = 44
\]

Since when \(x = -4\), we find that \(y = 44\) and not \(y = 0\), the point \((-4, 0)\) is **not** a solution to the equation \(y = x^2 - 7x\).