Is (–3, 2) a solution to the equation y = x2 − –3x − –2?

To determine if the point \((-3, 2)\) is a solution to the equation \(y = x^2 - (-3)x - (-2)\), we first clarify the equation. The expression simplifies to:

\[
y = x^2 + 3x + 2
\]

Now, we will substitute \(x = -3\) into the equation and see if the resulting \(y\) value is equal to 2.

Substituting \(x = -3\):

\[
y = (-3)^2 + 3(-3) + 2
\]

Calculating each term:

\[
(-3)^2 = 9, \quad 3(-3) = -9, \quad \text{and the constant } 2 \text{ remains as is.}
\]

Putting it all together:

\[
y = 9 - 9 + 2
\]

So,

\[
y = 0 + 2 = 2
\]

Since we find that \(y = 2\) when \(x = -3\), the ordered pair \((-3, 2)\) does satisfy the equation.

Therefore, the point \((-3, 2)\) is indeed a solution to the equation \(y = x^2 + 3x + 2\).