Is (–2, 3) a solution to the equation y = –2x2?

To determine if the point \((-2, 3)\) is a solution to the equation \(y = -2x^2\), we can substitute \(x = -2\) into the equation and see if it results in \(y = 3\).

Starting with the equation:

\[
y = -2x^2
\]

Substituting \(x = -2\):

\[
y = -2(-2)^2
\]

Calculating \((-2)^2\):

\[
(-2)^2 = 4
\]

Now substituting back into the equation:

\[
y = -2 \cdot 4 = -8
\]

The calculated value of \(y\) is \(-8\). The point \((-2, 3)\) has \(y = 3\), so:

\(-8 \neq 3\)

Thus, \((-2, 3)\) is **not** a solution to the equation \(y = -2x^2\).