To determine if the point \((-2, 3)\) is a solution to the equation \(y = -2x^2\), we can substitute \(x = -2\) into the equation and see if it results in \(y = 3\).
Starting with the equation:
\[ y = -2x^2 \]
Substituting \(x = -2\):
\[ y = -2(-2)^2 \]
Calculating \((-2)^2\):
\[ (-2)^2 = 4 \]
Now substituting back into the equation:
\[ y = -2 \cdot 4 = -8 \]
The calculated value of \(y\) is \(-8\). The point \((-2, 3)\) has \(y = 3\), so:
\(-8 \neq 3\)
Thus, \((-2, 3)\) is not a solution to the equation \(y = -2x^2\).